Answer:
B
Step-by-step explanation:
We have the function:
[tex]f(x)=x^2-5x[/tex]
And we are given that:
[tex]f(n)=-4[/tex]
And we want to find the value of n such that this is true.
So, let's substitute f(x) for -4 and x for n. This yields:
[tex]-4=n^2-5n[/tex]
Let's solve for n. First, add 4 to both sides:
[tex]n^2-5n+4=0[/tex]
This is a quadratic. We can solve by factoring:
[tex](n-1)(n-4)=0[/tex]
Zero Product Property:
[tex]n-1=0\text{ or } n-4=0[/tex]
Solve for n for each equation:
[tex]n=1\text{ or }n=4[/tex]
So, n can be either 1 or 4.
Our of our answer choices, the correct answer is B.
And we're done!
