During a school tournament, Team A had 10 of its 12 team members present.
Team B had 13 of its 15 players present.
Which team had the lesser percent of its team present at the tournament?

Respuesta :

Answer:

Team A.

Step-by-step explanation:

We know that Team A had 10 of its 12 members present.

We can write this as the following fraction:

[tex]A=10/12[/tex]

We can convert this to a decimal by dividing the two numbers. Use a calculator:

[tex]A\approx.8333[/tex]

And we can convert this to a percent by moving the decimal too places to the right and by adding a percent sign:

[tex]A\approx83.33\%[/tex]

So, about 83.33% of members on Team A was present.

We know that Team B had 13 of its 15 members present.

We can write this as the following fraction:

[tex]B=13/15[/tex]

Again, we can convert this to a decimal by dividing the two numbers:

[tex]B\approx 0.8667[/tex]

Change this to a percent:

[tex]B\approx86.67\%[/tex]

So, Team A had a participation rate of 83.33% while Team B had a participation rate of 86.67%.

So, the team that had the lesser percent of the team present at the tournament is Team A.

And we're done!

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