contestada


A tennis ball is dropped from 1.77 m above
the ground. It rebounds to a height of 1.05 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s2. (Let
down be negative.)
Answer in units of m/s.

Respuesta :

MathPhys

Answer:

5.89 m/s

Explanation:

Given:

Δy = 1.77 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (1.77 m)

v = 5.89 m/s

Otras preguntas

Q&A Education