A coroner arrives at a murder scene at 10p.m. She finds the temperature of the body to be 86.3 degrees F. She waits one​ hour, takes the temperature​ again, and finds it to be 83.3 degrees F. She notes that the room temperature is 69 degrees F. Assuming that the temperature of the body was 98.6F when the murder​ occurred, when was the murder​ committed?

Give an aproximate hour and tell weather it was p.m or a.m.

Respuesta :

5 - 6 pm

if the temperature drops 3 degrees per hour. so how many hours would it take to go from 98.6 to 86.3

98.6-86.3=12.3

3 goes into 12 4 times.

10 pm - 4 hours is 6pm.

if you figure in the .3

you come to approximately 5pm

The time of the murder can be designated around:

5 - 6 pm

Temperature

Given that,

Time of witnessing the murder = 10:00 PM

Body's temperature at that time = 86.3° F

Body's temperature after 1 hour = 83.3° F

So,

The temperature dropping every hour = 3° F

The reduction in the temperature of the body from normal temperature to 86.3° F at 10 PM:

= 98.6° F - 86.3° F

= 12.3° F

Now,

To find the duration since the body is lying there, we will be dividing the total drop in temperature till 10 PM by the drop in temperature every hour:

= 12.3/3

= 4.1 hours

So,

4 hours before 10:00 PM(2200 hours)

= 2200 - 4 hours

= 1800 hours

∵ 6:00 PM is the time when the person would have been murdered.

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