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A bicycle with an initial velocity of +6 m/s accelerates at a rate of +2 m/s2 for 3 seconds. What distance does the bicycle travel during this time?​

Respuesta :

MathPhys

Answer:

27 m

Explanation:

Given:

v₀ = 6 m/s

a = 2 m/s²

t = 3 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (6 m/s) (3 s) + ½ (2 m/s²) (3 s)²

Δx = 27 m

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