Two astronauts of identical mass are connected by a taut cable of negligible mass, as shown in the figure above, and are initially at rest with respect to a nearby space station. Astronaut Y pulls on the cable toward herself with considerable force. Which of the following describes the direction of the velocity of the center of mass of the two astronauts after Astronaut Y pulls on the cable?

It generates a voltage throughout the cable while the astronaut falls on either the wire. At other ends of the spectrum or cable, the tension will be similar. As such, with both astronauts, there would be the same energy, although throughout the opposite way.
Thus, the net force seems to be essentially negative on the machine. And therefore the mass center stays stationary.

ajeigbeibraheem ajeigbeibraheem · Answer 2 · 2021-11-16T13:36:51+01:00

The direction of the velocity of the center of mass of the two astronauts does not move after Astronaut Y pulls on the cable.

From the given information, the pulling of the cable by astronaut Y builds and generates tension in the cable.

At the two ends of the cable, this tension will be the same. As such, there exist same force on the two astronauts which occurs in an opposite direction.

Therefore, this gives a net force that is equal to zero thereby making the center of the mass to remian stationary and not to move.

Learn more about force here:

https://brainly.com/question/18531588?referrer=searchResults