Respuesta :
Answer:
The animal cell will take in water until it eventually swells or burst
Explanation:
Osmosis is an important phenomenon that drives the movement of water across membranes. It is defined as the movement of water molecules from a region of high water concentration/low solute concentration to a region of low water concentration/high solute concentration across a semi-permeable membrane.
In this case, the animal cell with a molar concentration of 2.0M is placed in 0.0M and 1.0M sucrose solutions. This means that the cell is placed in an hypotonic solution (solution with low solute concentration), hence, water will move from the extracellular solution into the animal cell since the solute concentration in the cell is more. The animal cell will begin to swell and eventually burst.
In hypotonic solutions, the concentration of solute is lower than the concentration inside the cell. If a cell (2M) is placed in two solutions (0M and 1M), water will move toward the cell interior, swelling it.
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When talking about solutions, we can classify them as follows,
- Hypertonic ⇒ A solution has a higher concentration of solute than the cell. This means that in the cell interior, the solute concentration is lower than in the solution itself.
- Isotonic ⇒ The concentration of solute turns to be the same inside the cell and outside.
- Hypotonic ⇒ The concentration of solute in the solution is lower than the concentration inside the cell. The solute is more diluted in the solution than in the cell.
Water is considered to be a hypotonic solution.
When a cell is in a hypotonic solution, through osmosis, water moves toward the cell.
Osmosis occurs when two dilutions of different concentrations -in this example, the interior of the cell and the solution- are separated by a semipermeable membrane.
The membrane allows the pass of water but not solute.
Hence, water can move from the most diluted side to the less diluted one.
Water tends to go from the hypotonic solution to the cell interior and keeps doing so until concentrations are equal in the cell interior and exterior.
As water enters the cell, the cell begins to enlarge and becomes bigger-sized.
Because isolated cells can not limit the amount of water moving in, it keeps swelling until the membrane can not stretch anymore, and lysis occurs. It bursts.
Under natural conditions, the body regulates the extracellular fluids to avoid cells swelling until they burst.
What we need to consider is
- When a cell with a semipermeable membrane is placed in a hypotonic solution, water enters the cell.
- When a cell with a semipermeable membrane is placed in an isotonic solution, there is no water movement.
- When a cell with a semipermeable membrane is placed in a hypertonic solution, water gets out of the cell.
In simple words, in the proposed experiment, sucrose can not cross the membrane, but water can. So,
To solve this problem, we know that
- The molar concentration in the interior of this animal cell is 2.0M.
- There are two cucrose solutions ⇒ 0M and 1.0 M
In both cases, the concentration in the interior of the cell is higher than the concentration in the solution.
In both cases the cell is in a hypotonic solution, meaning that water will get into the cell.
- Water will move into the cell from the solution
- Both cells will swell as water moves in.
- The cell placed in a solution 1 M will reach equilibrium before the cell placed in a solution 0 M.
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Related link: https://brainly.com/question/122954?referrer=searchResults
