PLSSSSSSSSSSS HELP I HAVE BEEN STUCK ON THIS FOR DAYS
(NO GRAPH JUST THE EQUATION)

Graph the following lines and write the equation in slope-intercept form.


Through the points (5,6) and (−1,4).

(you only need to write the equation y=mx+b for this problem)

Respuesta :

Space

Answer:

y = 1/3x + 13/3

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Step 1: Find slope m

[tex]m=\frac{4-6}{-1-5}[/tex]

[tex]m=\frac{-2}{-6}[/tex]

[tex]m=\frac{1}{3}[/tex]

y = 1/3x + b

Step 2: Find y-intercept b

4 = 1/3(-1) + b

4 = -1/3 + b

b = 13/3

Step 3: Write linear equation

y = 1/3x + 13/3

Answer:

y = (1/3)x + 13/3

Step-by-step explanation:

1. Find the slope (m)

slope = change in y divided by change in x

m= [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} } = \frac{6-4}{5-(-1)} = \frac{2}{5+1} = \frac{2}{6} = \frac{1}{3}[/tex]

2. Subsitute 1/3 for m and pick one point to plug into y =mx+b

Ex: (5, 6) -> y= 6 x = 5

6 = 1/3(5) + b

3. Simplify: 6 = 1/3(5) + b

6 = 5/3 + b

4. Solve for b (isolating the variable) by adding 1/3 to both sides

6 - 5/3 = 5/3 - 5/3  + b

5. Simplify: 6 - 5/3 = 5/3 - 5/3  + b

18/3 - 5/3 = b -> 13/3 = b

5. plug in 13/3 for b and 1/3 for m in y = mx + b

y = mx + b -> y = (1/3)x + 13/3

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