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At the end of the school day, at exactly 2:30 pm, a group of students run out of the school building and reach the edge of the school property at 2:30:45 s. Which of the following correctly describes the motion in terms of time?
Question 2 options:

A)

t1= 0, t2 = 2:30:45 s, ∆t = 45 s

B)

t1= 2:30, t2 = 45 s

C)

∆t = 2:30

D)

t2= 2:30:45 s, ∆t = 45 s

Respuesta :

Explanation:

Initial time, t₁ = 2:30 pm

Final time, t₂ = 2:30:45

We need to find the motion of students in terms of time. Final time is 45 seconds more than the initial time.

Change in time,

[tex]\Delta t=t_2-t_1\\\\\Delta t=2:30:45-2.30\\\\\Delta t=45\ s[/tex]

Hence, this is the required solution.

snehashish65

The students need 45 seconds to reach out at the edge of the school property with the final interval of 2:30:45 s. Hence, option (D) is correct.

What is a time interval?

The difference between the moment of starting an event and the completion of the same is known as the time interval.

Given data -

The exact time to start the day at school is, t1 = 2:30 pm.

The time given to reach the edge of the school property is, t2 = 2:30:45 s.

In order to describe the motion, we need to obtain the change in the time interval. Then the expression for the change in the time interval is,

Δt = t2 - t1

Solving as,

Δt = 2:30:45 - 2:30

Δt = 45 s

Thus, we can conclude that the students need 45 seconds to reach out at the edge of the school property with the final interval of 2:30:45 s.

Learn more about the time interval here:

https://brainly.com/question/25996105

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