The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telescope is 9.21 × 104 N, and the mass of Earth is 5.98 × 1024 kg, what is the mass of the telescope? Round the answer to the nearest whole number.

Respuesta :

Answer:

11121.19 kg

Explanation:

Given that,

the gravitational force between Earth and the telescope is [tex]9.21\times 10^4\ N[/tex]

Mass of the Earth is [tex]5.98\times 10^{24}\ kg[/tex]

The center of the Hubble space telescope is 6940 km from Earth’s center.

We know that, the force of gravity is given by the formula as follows :

[tex]F=\dfrac{GmM}{r^2}[/tex]

m is mass of telescope and M is mass of Earth

So,

[tex]m=\dfrac{Fr^2}{GM}\\\\m=\dfrac{9.21\times 10^4\times (6940\times 10^3)^2}{6.67\times 10^{-11}\times 5.98\times 10^{24}}\\\\m=11121.19\ kg[/tex]

So, the mass off the telescope is 11121.19 kg

Q&A Education