Answer:
Mass of Cl₂ produced 12.78 g
Explanation:
Given data:
Mass of MnO₂ = 16 g
Mass of HCl = 30.0 g
Mass of Cl₂ produced = ?
Solution:
Chemical equation:
MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O
Number of moles of MnO₂:
Number of moles = mass / molar mass
Number of moles = 16 g/ 87 g/mol
Number of moles = 0.18 mol
Number of moles of HCl:
Number of moles = mass / molar mass
Number of moles = 30 g/ 36.46 g/mol
Number of moles = 0.82 mol
Now we will compare the moles of Cl₂ with MnO₂ and HCl.
MnO₂ : Cl₂
1 : 1
0.18 : 0.18
HCl : Cl₂
4 : 1
0.82 : 1/4×0.82 = 0.205 mol
The number of moles of Cl₂ formed by HCl are less it will limiting reactant.
Mass of Cl₂ formed:
Mass = number of moles × molar mass
Mass = 0.18 mol × 71 g/mol
Mass = 12.78 g
