Answer:
Empirical formula is C₂H₆O.
Explanation:
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number
Given data:
Percentage of hydrogen = 13.3%
Percentage of carbon = 52.0%
Percentage of oxygen = 34.7%
Empirical formula = ?
Molecular formula = ?
Solution:
Number of gram atoms of H = 13.3 / 1.01 = 13 .17
Number of gram atoms of O = 34.7 / 16 = 2.17
Number of gram atoms of C = 52.0 / 12 = 4.3
Atomic ratio:
C : H : O
4.3/2.17 : 13.17/2.17 : 2.17/2.17
2 : 6 : 1
C : H : O = 2 : 6 : 1
Empirical formula is C₂H₆O.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
n = 46 / 158
The relative molecular mass of compound is not correct.
