please help!! If the wind is blowing at 20 miles per hour, you can find the wind-chill temperature W (in degrees Fahrenheit) by using the equation W = 1.42T - 38.5, where T is the actual temperature (in degrees Fahrenheit). Solve this equation for T and write a reason for each step. What is the actual temperature if the wind chill temperature is -24.3°F and the wind is blowing at 20 miles per hour? thank you

-24.3 = 1.42T - 38.5

first, move -38.5 to the other side of the equal sign. because you’re moving to a different side, you must change the negative sign to a positive.

14.2 = 1.42T

now, you have to divide both numbers by 1.42 to isolate T.

10 = T

The actual temperature is 10°F.

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eudora eudora · Answer 2 · 2021-12-09T11:59:01+01:00

If the wind chill temperature is -24.3°F, actual temperature of the wind will be 10°F.

Equation for the chill temperature has been given as,

W = 1.42T - 38.5

Here, W = Chill temperature

T = Actual temperature

Solve this equation for the value of T,

W = 1.42T - 38.5

W + 38.5 = 1.42T - 38.5 + 38.5 (Add 38.5 on each side)

W + 38.5 = 1.42T

[tex]T=\frac{W+38.5}{1.42}[/tex] (Divide each side by 1.42)

For W = -24.3°F

[tex]T=\frac{-24.3+38.5}{1.42}[/tex] (Substitute the value of W in the equation)

T = 10° F

Therefore, actual temperature will be 10°F if the wind chill temperature is -24.3°F.

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