Respuesta :

TheSection

Answer:

58.94 mL

Explanation:

V1 = 48.3 mL             V2 = v mL

T1 = 22 degree celsius OR 295 k         T2 = 87 degree celsius OR 360 k

We will use the gas equation:

PV = nRT

Since the Pressure (p) , number of moles (n) and the universal gas constant(R) are all constants in this given scenario,

we can say that

V / T = k , (where k is a constant)

Since this is the first case,

V1 / T1 = k --------------------(1)

For case 2:

Since we have the same constants, the equation will be the same

V / T = k (where k is the same constant from before)

V2 / T2 = k (Since this is the second case) ------------------(2)

From (1) and (2):

V1 / T1 = V2 / T2

Now, replacing the variables with the given values

48.3 / 295 = v / 360

v = 48.3*360 / 295

v = 58.94 mL

Therefore, the final volume of the gas is 58.94 mL

samueladesida43

The volume of the sample at the final temperature is 58.94mL

CHARLE'S LAW EQUATION:

  • The volume of a given gas at a particular temperature can be calculated by using Charles law equation, which is as follows:

V1/T1 = V2/T2

Where;

  1. V1 = initial volume of gas (mL)
  2. V2 = final volume of gas (mL)
  3. T1 = initial temperature of gas (K)
  4. T2 = final temperature of gas (K)

According to this question,

  • V1 = 48.3mL
  • T1 = 22°C = 22 + 273 = 295K
  • T2 = 87°C = 87 + 273 = 360K
  • V2 = ?

48.3/295 = V2/360

295 × V2 = 48.3 × 360

295V2 = 17388

V2 = 17388 ÷ 295

V2 = 58.94mL

  • Therefore, the volume of the sample at the final temperature is 58.94mL.

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