Answer:
-3x^3-16x^2-14x+8
Step-by-step explanation:
[tex](x+4)(-3x^2-4x+2)\\\\Distribute\:parentheses\\\\=x\left(-3x^2\right)+x\left(-4x\right)+x\times\:2+4\left(-3x^2\right)+4\left(-4x\right)+4\times \:2\\\\Apply\:minus-plus\:rules\\+\left(-a\right)=-a\\\\=-3x^2x-4xx+2x-4\times\:3x^2-4\times\:4x+4\times\:2\\\\Simplify\\-3x^2x-4xx+2x-4\times\:3x^2-4\times\:4x+4\times\:2:\\\\\quad -3x^3-16x^2-14x+8\\\\=-3x^3-16x^2-14x+8[/tex]
