Answer:
[tex]\frac{14}{9} = 1\frac{5}{9} \\\\1.5[/tex]
Step-by-step explanation:
[tex](1+1/3)^2-2/9\\\\= \left(1+\frac{1}{3}\right)^2-\frac{2}{9}\\\\\left(1+\frac{1}{3}\right)^2=\frac{4^2}{3^2}\\\\=\frac{4^2}{3^2}-\frac{2}{9}\\\\\frac{4^2}{3^2}=\frac{16}{9}\\\\=\frac{16}{9}-\frac{2}{9}\\\\\mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\=\frac{16-2}{9}\\\\\mathrm{Subtract\:the\:numbers:}\:16-2=14\\=\frac{14}{9}[/tex]
