Answer:
Step-by-step explanation:
Hello,
[tex](1+1/3)^2-\dfrac{2}{9}=\left( \dfrac{3+1}{3}\right)^2-\dfrac{2}{9}\\\\=\dfrac{16}{9}-\dfrac{2}{9}\\\\=\dfrac{16-2}{9}\\\\=\boxed{\dfrac{14}{9}\\\\}[/tex]
Thanks
