Answer:
Step-by-step explanation:
a). Mean of the given data set = [tex]\frac{32+28+18+40+22}{5}[/tex]
= 28
b). x [tex]x-\overline{x}[/tex] [tex](x-\overline{x})^2[/tex]
32 32-28 = 4 16
28 28 - 28 = 0 0
18 18 - 28 = -10 100
40 40 - 28 = 12 144
22 22 - 28 = -6 36
[tex]\sum({x-\overline x})^2[/tex] = 296
c). Standard deviation = [tex]\sqrt{\frac{\sum (x-\overline{x})^2}{n}}[/tex]
= [tex]\sqrt{\frac{296}{5} }[/tex]
= 7.69
d). Mean of the new set of weights = [tex]\frac{32+33+34+35+36}{5}[/tex]
= 34
Since mean of the data set is more close to each data, standard deviation will be less than the deviation given in part (c).
