Explanation:
we first find acceleration by
V=u +at (v is the final velocity,u the initial velocity,a the acceleration and t the time taken)
v=25 m/s
u=0
t=3.6s
substituting we get
25=0 + a (3.6)
25=3.6a (diving both sides by 3.6 we get)
a=6.94 m/s^2
to find distance we use the equation v^2=u^2 + 2ad
25^2 =0^2 + 2 (6.94)do
625=13.88d (dividing both sides by 13.88 we get );
d=45m
