A plane takes off and travels at an angle of 50° north of east at 90 mph for 3 hours. It then adjusts its path to head 30° west of north and travels in that direction for an hour at a speed of 100 mph. Approximately how far away is the plane from its starting point?

Respuesta :

Answer:

303.8 miles.

Step-by-step explanation:

Using the given information, draw a figure as shown below.

90 mph for 3 hours = 270 miles

100 mph of 1 hour = 100 miles

In triangle ABC,

[tex]\angle ABC=50^{\circ}+50^{\circ}=100^{\circ}[/tex]

Using cosine formula,

[tex]AC^2=AB^2+BC^2-2(AB)(BC)\cos B[/tex]

[tex]AC^2=(270)^2+(100)^2-2(270)(100)\cos (100^{\circ})[/tex]

[tex]AC^2=72900+10000-54000\cdot\left(-0.174\right)[/tex]

[tex]AC^2=92296[/tex]

Taking square root on both sides.

[tex]AC=\sqrt{92296}[/tex]

[tex]AC\approx 303.8[/tex]

Therefore,  the plane is 303.8 miles from its starting point.

Ver imagen erinna

Answer:

271 miles

Step-by-step explanation:

Q&A Education