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The velocity of a 2 kg object initially moving at ( – 2i +3j -5k) m/s changes to ( i +3j+4k) m/s after 3 s. The magnitude of the force acting on the body is (a) 2√3 N (b) 2√10 N (c) 6√3 N (d) 12√3 N

Respuesta :

MathPhys

Answer:

(b) 2√10 N

Explanation:

Impulse = change in momentum

FΔt = mΔv

F (3 s) = (2 kg) √((1 − -2)² + (3 − 3)² + (4 − -5)²) m/s

F (3 s) = (2 kg) √(3² + 0² + 9²) m/s

F (3 s) = (2 kg) (3√10 m/s)

F = 2√10 N

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