Respuesta :
Answer:
4
Step-by-step explanation:
If you replace x with 3 in the expression you will get an indefenite form (0/0)
So there two methods.
The easiest one is applying The hospital rule
Derivate the expression firsr but separatly.
● (x^2 -2x -3)' = 2x - 2
● (x-3)' = 1
When x tends to 3
Lim(x^2-2x-3/x-3) = lim (2x-2/1) = 6-2 = 4
The roots of the nominator are:
[tex] \frac{ 2 ( + - ) \sqrt{4 + 12}}{2} = \frac{ 2 ( + - ) 4}{2} = 3 \: and \: - 1[/tex]
Which means that the nominator can be written as:
[tex] {x}^{2} - 2x - 3 = (x - 3)(x + 1)[/tex]
Thus we compute the limit as shown below:
[tex]lim( \frac{ {x}^{2} - 2x - 3}{x - 3})(x - > 3) = lim( \frac{(x - 3)(x + 1)}{x - 3})(x - > 3) = lim( x + 1)(x - > 3) = 4[/tex]