Step-by-step explanation:
a)
put the formula....
l × b = A
or,
[tex] l × ( x+2 ) = 4{x}^{2} + 5x - 6[/tex]
or,
[tex]l \times(x + 2) = (4x - 3)(x + 2) [/tex]
or,
[tex]l = (4x - 3) + (x + 2) - (x + 2)[/tex]
Therefore,
[tex]l = 4x - 3[/tex]
b)
we know the value of x,
l = 4x-3 b = x+2
= 4× 11 -3 = 11+2
= 41cm = 13cm
Area= l × b
= 41 × 13
= 533 cm^2
c)
square = l × l
Given,
121x^2 - 22x + 1
or, 121x^2 -11x -11x +1
or, 11x ( 11x -1 ) - 1 ( 11x -1 )
Therefore,
dimension is ( 11x-1 )( 11x -1 )
d) x= 25
l= 11x -1
= 11× 25 -1
= 274cm
Area= l^2
= 75076 cm^2
Area of frame = (12cm)^2
= 144cm^2
Area of painting= ( 1225-144 )cm^2
= 1081 cm^2
(length)^2 = Area
or, l^2 = (1081)
or 1^2 = (32.8)^2
Therefore, dimension of painting is 32.8cm