Answer :
[tex]\circ\sf\:32{\huge(}\dfrac{3y}{8}+\dfrac{3}{4}{\huge)}-32(y-1)-32{\huge(}-\dfrac{5y}{16}+\dfrac{2}{32}{\huge)}[/tex]
[tex]\circ\sf\:{\huge(}\dfrac{(3\times 32)y}{8}+\dfrac{(3\times 32)}{4}{\huge)}-(32y-32)-{\huge(}-\dfrac{(5\times 32)y}{16}+\dfrac{(2\times 32)}{32}{\huge)}[/tex]
[tex]\circ\sf\:[(3\times 4)y+(3\times 8)]-32y+32+(5\times 2)y-2[/tex]
[tex]\circ\sf\:12y+24-32y+32+10y-2[/tex]
[tex]\circ\sf\:(12y-32y+10y)+(24+32-2)[/tex]
[tex]\circ\sf\:54-10y[/tex]
[tex]\circ\:\boxed{\bf{\purple{2(27-5y)} }}[/tex]
