1st answer is n and 2nd is 3n.
Step-by-step explanation:
1st one....
first term (a) = 1
common difference (d) = 2-1 =1
no. of term (n) = n
Now,
nth term = a + ( n-1 ) d
= 1 + ( n-1 ) 1
= 1 + n - 1
= n
2nd one...
first term (a) = 3
common difference (d) = 6-3 =3
no. of term (n) = n
Now,
nth term = a + ( n-1 ) d
= 3 + ( n-1 ) 3
= 3 + 3n - 3
= 3n
