Answer:
[tex]V=7.68\times 10^{-4}\ L[/tex]
Explanation:
It is given that,
Weight of silver coin, m = 8.062 grams
The density of silver, [tex]d=1.049 \times 10^4\ kg/m^3[/tex]
We need to find the volume of the coin.
Density = mass per unit volume
[tex]d=\dfrac{m}{V}\\\\\implies \ V=\dfrac{m}{d}\\\\V=\dfrac{8.062\times 10^{-3}\ kg}{1.049\times 10^4\ kg/m^3}\\\\V=7.68\times 10^{-7}\ m^3[/tex]
Since, [tex]1\ L=10^{-3}\ m^3[/tex]
⇒ [tex]1\ m^3=10^3\ L\\\\7.68\times 10^{-7}\ m^3=7.68\times 10^{-7}\times 10^3\ L\\\\V=7.68\times 10^{-4}\ L[/tex]
Hence, the volume is [tex]7.68\times 10^{-4}\ L[/tex].
