Answer:
[tex] \boxed{\sf Acceleration \ of \ the \ car \ (a) = 2.4 \ m/s^2} [/tex]
Given:
Initial speed (u) = 0 m/s (Starts from rest)
Final speed (v) = 30 m/s
Distance travelled (s) = 130.5 m
To Find:
Acceleration of the car (a)
Explanation:
From equation of motion we have:
[tex] \boxed{ \bold{ {v}^{2} = {u}^{2} + 2as}}[/tex]
By substituting value of v, u & s in the equation we get:
[tex] \sf \implies {25}^{2} = {0}^{2} + 2a \times 130.5 \\ \\ \sf \implies {25}^{2} = 2a \times 130.5 \\ \\ \sf \implies {25}^{2} = 261a \\ \\ \sf \implies 625 = 261a \\ \\ \sf \implies 261a = 625 \\ \\ \sf \implies a = \frac{625}{261} \\ \\ \sf \implies a = 2.4 \: m {s}^{ - 2} [/tex]
