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A 15-foot log is cut into two pieces. How long is each piece if the longer piece is 1.5 feet shorter than twice the shorter piece?

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Answer:

Length of shorter piece is 5.5 foot and length of longer piece is 9.5 foot.

Step-by-step explanation:

It is given that a 15-foot log is cut into two pieces.

The longer piece is 1.5 feet shorter than twice the shorter piece.

Let the length of shorter piece be x foot.

Length of longer piece = (2x-1.5) foot

Combine length of both pieces = x+(2x-1.5) foot

Now,

[tex]x+(2x-1.5)=15[/tex]

[tex]3x-1.5=15[/tex]

[tex]3x=15+1.5[/tex]

[tex]3x=16.5[/tex]

Divide both sides by 3.

[tex]x=5.5[/tex]

Length of shorter piece = 5.5 foot. So, length of longer piece is

[tex]2(5.5)-1.5=11-1.5=9.5[/tex]

Therefore, length of shorter piece is 5.5 foot and length of longer piece is 9.5 foot.

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