Answer:
The fire hydrant = 9 meters west and south of the tower = 58 m
Step-by-step explanation:
The coordinate as the origin includes the Fire A and Fire B
Given that
Fire A is 75 meters east and south of the tower is 40 meters
So, it is presented (75,-40)
And, the fire B is 37 west and south of the tower is 64 meters
So, it is presented (-37,-64)
Now at a point O (x,y) divides AB a line segment as A(x_1, y_1) and B(x_2, y_2)
So,
[tex]x = \frac{n}{n+m} (x_2 - x_1) + x_1\\\\y = \frac{n}{n+m} (y_2 - y_1) + y_1[/tex]
Now it divides in three-fourth
So,
[tex]x = \frac{n}{n+m} (x_2 - x_1) + x_1\\\\= \frac{3}{4} (-37-75) + 75\\\\= \frac{3}{4} (-112) + 75\\\\= -84 + 75\\\\= -9[/tex]
[tex]y = \frac{n}{n+m} (y_2 - y_1) + x_1\\\\= \frac{3}{4} (-64-(-40)) + (-40)\\\\= \frac{3}{4} (-18) -40\\\\= -18-40\\\\= -58[/tex]
Hence, these two are to be considered