Answer:
The value is [tex]K_C = \frac{40}{600}[/tex]
Explanation:
From the question
The equation given is
NiO(s) + H2(g) ⇌ Ni(s) + H2O(g) Kc=40 (1)
NiO(s) +CO(g) ⇌ Ni(s) +CO2(g) Kc=600 (2)
Generally the reverse of the second equation as shown below
Ni(s) +CO2(g) ⇌ NiO(s) + CO(g) (3)
The equilibrium constant becomes [tex]K_c ' = \frac{1}{600}[/tex]
Now adding 1 and 3 we obtain
NiO(s) + H2(g)+ Ni(s) +CO2(g) ⇌ Ni(s) + H2O(g)+NiO(s) + CO(g)
CO2(g) + H2(g) ⇌ CO(g) + H2O(g)
Hence the equilibrium constant for the resulting equation is mathematically evaluated as
[tex]K_C = K_c' * K_c[/tex]
=> [tex]K_C = \frac{1}{600} * 40[/tex]
=> [tex]K_C = \frac{40}{600}[/tex]
