Answer:
A. 93,586.6 g
B. 1.982 × 10⁻⁷ g
C. 29.77 g
Explanation:
A. Find the volume using the given formula.
V = (4/3)πr³
V = (4/3)π(10.5)³
V = (4/3)π(1157.625)
V = 1543.5π
V = 4849.05 cm³
Using the volume and density, solve for mass.
(4849.05 cm³) × (19.3 g/cm³) = 93,586.6 g
B. Convert mm to cm.
0.021 mm = 0.0021 cm
Use the formula for the volume of a cube.
V = s³
V = (0.0021)³
V = 9.261 × 10⁻⁹ cm³
Using the volume and density, solve for mass.
(9.261 × 10⁻⁹ cm³) × (21.4 g/cm³) = 1.982 × 10⁻⁷ g
C. You simply use the volume and density to solve for mass.
(37.3 mL) × (0.798 g/mL) = 29.77 g
Answer:
a) 93598.82 g
b) 1.98 x 10^-7 g
c) 29.76 g
Explanation:
a) radius of gold sphere = 10.5 cm
volume = [tex]\frac{4}{3}\pi r^3[/tex]
V = [tex]\frac{4}{3}*3.142* 10.5^3[/tex] = 4849.68 cm^3
if the density of gold = 19.3 g/cm^3
mass = density x volume
m = 19.3 x 4849.68 = 93598.82 g = 93.59 kg
b) edge length of platinum cube L= 0.021 mm = 0.0021 cm
Volume = [tex]L^{3}[/tex] = [tex]0.21^3[/tex] = 9.26 x 10^9 cm^3
If the density = 21.4 g/cm^3
mass = density x volume
m = 21.4 x 9.26 x 10^-9 = 1.98 x 10^-7 g
c) for a 37.3 mL of ethanol
density = 0.798 g/mL
mass m = 0.798 x 37.3 = 29.76 g
