Answer: Molar heat capacity C = 136.09 JK-1mole-1
Explanation:
Heat capacity,  C = Q/ ΔT
where C = heat capacity
Q =heat energy= Â Q = 330 J
ΔT is temperature difference =Change in temp =
ΔT = (28.7  +273)-( 21 + 273)= 7.7 K
But
No. of moles of benzene= mass / molar mass
 = 24.6g / 78.11g/mol
   = 0.3149 moles
Molar heat capacity C = Q/ nΔT
               = 330 / ( 0.3149 x 7.7 )
               = 136.09 JK-1mole-1