Answer:
[tex](h+g)(n)=4n+3[/tex]
Step-by-step explanation:
So we have the two functions:
[tex]h(n)=n+3\text{ and } g(n)=3n[/tex]
And we want to find (h+g)(n).
This is the same as: h(n)+g(n). So, substitute:
[tex]h(n)+g(n)\\=(n+3)+(3n)[/tex]
Combine like terms:
[tex]=4n+3[/tex]
So:
[tex](h+g)(n)=4n+3[/tex]
And we're done!
