Answer:
5.024 × 10⁻⁹ m
Explanation:
You need to use de Broglie's equation.
λ = h/mv
You have the velocity of the electron (1.43 × 10⁵ m/s), the mass of an electron (9.1 × 10⁻³¹ kg), and Planck's constant (6.626 × 10⁻³⁴ J·s). You now need to solve for wavelength (λ).
λ = (6.626 × 10⁻³⁴ J·s)/(9.1 × 10⁻³¹ kg)(1.43 × 10⁵ m/s)
λ = 5.024 × 10⁻⁹ m
The de Broglie wavelength is 5.024 × 10⁻⁹ m.
