On the number line below, Point B lies somewhere between Points A and C. If AB = \frac{1}{3} AC. Find BC. a 16 b 0 c 8 d 24

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Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the number line is not attached.

However, the following will guide you through

Given

[tex]AB = \frac{1}{3}AC[/tex]

Required

Determine BC

First, we need to get the fraction of BC using the following

[tex]AB + BC = AC[/tex]

Substitute [tex]\frac{1}{3}AC[/tex] for AB

[tex]\frac{1}{3}AC + BC = AC[/tex]

Make BC the subject of formula

[tex]BC = AC - \frac{1}{3}AC[/tex]

Take LCM

[tex]BC = \frac{3AC - AC}{3}[/tex]

[tex]BC = \frac{2AC}{3}[/tex]

[tex]BC = \frac{2}{3}AC[/tex]

This implies that you multiply the length of AC by 2/3 to get BC

Take for instance, AC = 24

BC will be:

[tex]BC = \frac{2}{3} * 24[/tex]

[tex]BC = \frac{48}{3}[/tex]

[tex]BC = 16[/tex]

Or if AC = 12

BC will be:

[tex]BC = \frac{2}{3} * 12[/tex]

[tex]BC = \frac{24}{3}[/tex]

[tex]BC = 8[/tex]

Or if AC = 36

BC will be:

[tex]BC = \frac{2}{3} *36[/tex]

[tex]BC = \frac{72}{3}[/tex]

[tex]BC = 24[/tex]

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