Answer:
There are 0.1 mililiters in 5 milimeters saline.
Step-by-step explanation:
A 2 % suspension means that 2 % of the volume of a given substance per each 100 milimeters of saline. That is:
[tex]r = \frac{V_{sub}}{V_{sal}}[/tex]
[tex]V_{sub} = r\cdot V_{sal}[/tex]
Where:
[tex]r[/tex] - Suspension ratio, dimensionless.
[tex]V_{sal}[/tex] - Saline volume, measured in milimeters.
[tex]V_{sub}[/tex] - Substance volume, measured in milimeters.
Given that [tex]r = 0.02[/tex] and [tex]V_{sal} = 5\,mL[/tex], the volume of the substance is:
[tex]V_{sub} = 0.02\cdot (5\,mL)[/tex]
[tex]V_{sub} = 0.1\,mL[/tex]
There are 0.1 mililiters in 5 milimeters saline.
