Respuesta :
Answer:
a. [tex]C(A(t)) = 2657 + 1330t - 35t^2[/tex]
b. the cost of the first 2 hours of operation is $5177
Explanation:
From the given information:
a. The factory's cost as a function of the number of hours of operation of the assembly line can be expressed as:
[tex]C(A(t)) = C ( 19t - \dfrac{1}{2}t^2)[/tex]
[tex]C(A(t)) = 2657 + 70 ( 19t - \dfrac{1}{2}t^2)[/tex]
[tex]C(A(t)) = 2657 + 1330t - 35t^2[/tex]
b. Replacing t = 2 in the above equation, we have:
[tex]C(A(t)) = 2657 + 1330t - 35t^2[/tex]
[tex]C(A(2)) = 2657 + 1330(2)- 35(2)^2[/tex]
[tex]C(A(2)) = 2657 + 2660- 140[/tex]
[tex]C(A(2)) =5317- 140[/tex]
[tex]C(A(2)) =5177[/tex]
Hence, the cost of the first 2 hours of operation is $5177
The activities that help in the management of the various managerial activities are the operational activities. These activities aid in the function of the different activities of the firm.
a. [tex]C(A(t))=2657+1330t-35t^{2} \\[/tex]
b. The cost of the first 2 hours of operation is $5177
a. The factory's cost as a function of the number of hours of operation of the assembly line can be expressed as:
[tex]C(A(t))=C(19t-\frac{1}{2}t^{2})\\C(A(t))=2657+70(19t-\frac{1}{2}t^{2})\\C(A(t))=2657+1330t-35t^{2}[/tex]
b. Replacing t = 2 in the above equation:
[tex]C(A(t))=2657+1330t-35t^{2} \\C(A(2))=2657+1330(2)-35(2)^{2}\\C(A(t))=2657+2660-140\\=5177[/tex]
Hence, the cost of the first 2 hours of operation is $5177
To know more about the calculation of the operation, refer to the link below:
https://brainly.com/question/22294801
