Find cos theta, please help!
Answer:
21/29
Step-by-step explanation:
[tex] \cos \theta = \frac{AC}{AB} = \frac{42}{58} = \frac{21}{29} \\ [/tex]
Answer:
21/29
Step-by-step explanation:
Recall that the cosine ratio is the adjacent side over the hypotenuse.
From the triangle, the adjacent side to angle Θ is 42. The hypotenuse (opposite from the right angle) is 58. Therefore:
[tex]\cos(\theta)=adj/hyp[/tex]
Substitute 42 for the adjacent side and 58 for the hypotenuse:
[tex]\cos(\theta)=42/58[/tex]
Reduce:
[tex]\cos(\theta)=21/29[/tex]
And we're done!