it is actually deceleration a
uzing v²= u²+2as where a is acceleration s is distance v is final speed and u is the initial speed
5²= 10²+2a(1600)
25=100+3200a
25-100=3200a
-75=3200a
a= -75/3200
=-0.0234m/s²
why the negative sign. it.shows that.the car is slowing down gradually. so the deceleration is 0.0234m/s²
