Answer:
[tex]\bold{E\ =\ \dfrac{6V-3}4=\dfrac32V-\dfrac34}[/tex]
Step-by-step explanation:
[tex]\bold{6+4E-6V\ =\ 3}\\\\{}\ \ -6+6V\qquad -6+6V\\\\\bold{4E\ =\ 3-6+6V}\\\\\bold{4E\ =\ 6V-3}\\\\\div4\quad\ \div4\\\\\bold{E\ =\ \frac{6V-3}4=\frac32V-\frac34}[/tex]
