Answer:
[tex]-\frac{42y}{x}[/tex]
Step-by-step explanation:
Apply the fraction rule: [tex]\frac{-a}{b}=-\frac{a}{b}[/tex]
[tex]=-\frac{336x^2y^3}{8x^3y^2}[/tex]
Divide the numbers: [tex]\frac{336}{8} =42[/tex]
[tex]=\frac{42x^2y^3}{x^3y^2}[/tex]
Apply the exponent rule: [tex]\frac{x^a}{x^b}=\frac{1}{x^{b-a}}[/tex]
[tex]\frac{x^2}{x^3}=\frac{1}{x^{3-2}}[/tex]
[tex]=\frac{42y^3}{y^2x^{3-2}}[/tex]
Subtract the numbers: [tex]\:3-2=1[/tex]
[tex]=\frac{42y^3}{xy^2}[/tex]
Apply the exponent rule: [tex]\frac{x^a}{x^b}=x^{a-b}[/tex]
[tex]\frac{y^3}{y^2}=y^{3-2}[/tex]
[tex]=\frac{42y^{3-2}}{x}[/tex]
Subtract the numbers: [tex]3-2=1[/tex]
[tex]=-\frac{42y}{x}[/tex]
