Answer:
s
Explanation:
It is given that, a physics problem you end up with m in the numerator and m/s in the denominator. It would mean that,
[tex]\dfrac{\text{numerator}}{\text{denominator}}=\dfrac{m}{m/s}[/tex]
m is metre and s is second
or
[tex]=\dfrac{m}{\dfrac{m}{s}}\\\\=\dfrac{s}{1}[/tex]
so, the unit of the answer is s.
