Respuesta :
Answer:
The mass of PCl₃ is 332.3 g.
The molecules of PCl₃ is [tex]1.45\times10^{24}\ g[/tex]
Explanation:
Given that,
Mass of P₄ = 75.0 g
Mass of Cl₂ = 275 g
We know that,
The reaction is
[tex]P_{4}+6Cl_{2}\Rightarrow 4PCl_{3}[/tex]
We need to calculate the moles of P₄
Using formula of moles
[tex]n=\dfrac{m}{M}[/tex]
Put the value into the formula
[tex]n=\dfrac{75.0}{123.89}[/tex]
[tex]n=0.61\ moles[/tex]
We need to calculate the moles of Cl₂
Using formula of moles
[tex]n=\dfrac{m}{M}[/tex]
Put the value into the formula
[tex]n=\dfrac{275}{70.906}[/tex]
[tex]n=3.89 moles[/tex]
We need to calculate the number of moles of [tex]4PCl_{3}[/tex]
Moles in 1 P₄ = 0.61
So, [tex]moles\ in\ 4PCl_{3} = 4\times0.61[/tex]
[tex]moles\ in\ 4PCl_{3}=2.42\ moles[/tex]
We need to calculate the mass of [tex]PCl_{3}[/tex]
Using formula of mass
[tex]m=M\times n[/tex]
Put the value into the formula
[tex]m=137.3\times2.42[/tex]
[tex]m=332.3\ g[/tex]
We need to calculate the molecules of [tex]PCl_{3}[/tex]
Using formula of molecules
[tex]molecules=n\times N[/tex]
Where, n = number of moles
N = avagadro number
Put the value into the formula
[tex]molecules=2.42\times6.023\times10^{23}[/tex]
[tex]molecules=1.45\times10^{24}\ g[/tex]
Hence, The mass of PCl₃ is 332.3 g.
The molecules of PCl₃ is [tex]1.45\times10^{24}\ g[/tex]
