Answer:
(0, 0.04)
Explanation: Given that At time t = 0, a particle is at rest in the x‐y plane at the coordinates (x0, y0) = (6, 0) in. If the particle is then subjected to the acceleration components ax = 0.5 − 0.35t in./sec^2 and ay = 0.15t − 0.02t^2 in./sec^2.
differentiate ax and ay twice. That is, second derivatives to get the position
dax/dt = − 0.35
d^2ax/dt^2 = 0
and
day/dt = 0.15 − 0.04t
d^2ay/dt^2 = 0.04
the coordinate of the particle after t = 6 sec will be (0, 0.04)
the graph will be linear
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l---- \----------------------------------------------------------------------------
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