Answer:
[tex]\frac{2x^2-3x}{7}[/tex]
Step-by-step explanation:
[tex]\frac{2x-3}{x}[/tex] ÷ [tex]\frac{7}{x^2}[/tex]
=> [tex]\frac{2x-3}{x}[/tex] × [tex]\frac{x^2}{7}[/tex]
=> [tex]\frac{2x-3}{7}[/tex] × [tex]\frac{x^2}{x}[/tex]
=>[tex]\frac{x(2x-3)}{7}[/tex]
=> [tex]\frac{2x^2-3x}{7}[/tex]
