How many moles of NaOH are present in 65.00 g of NaOH(s)? *
Answer:
Explanation:
To find the number of moles we must first find the molar mass of the compound after that we use the formula
[tex]n = \frac{m}{M} [/tex]
where
n is the number of moles
M is the molar mass
m is the mass
M(Na) = 23 , M(O) = 16 , M(H) = 1
Molar mass ( NaOH ) = 23+ 16 + 1
= 40 g/mol
mass = 65 g
Substitute the values into the above formula and solve
That's
[tex]n = \frac{65}{40} = \frac{13}{8} [/tex]
We have the final answer as
Hope this helps you