Answer:
d = √29
Explanation:
[tex]d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\x_1 =4\\y_1 =1\\x_2=2\\y_2 =6\\\\d=\sqrt{\left(2-4\right)^2+\left(6-1\right)^2}\\\\d = \sqrt{(-2)^2+(5)^2}\\ \\d = \sqrt{4+25}\\ \\d = \sqrt{29}[/tex]
