Answer:
1). [tex]\frac{2}{x^{2}-x-12 }=\frac{2}{(x+3)(x-4)}[/tex]
2). [tex]\frac{1}{x^{2}-16 }=\frac{1}{(x-4)(x+4)}[/tex]
Step-by-step explanation:
In this question we have to write the fractions in the factored form.
Rational expressions are [tex]\frac{2}{x^{2}-x-12 }[/tex] and [tex]\frac{1}{x^{2}-16 }[/tex].
1). [tex]\frac{2}{x^{2}-x-12 }[/tex]
Factored form of the denominator (x² - x - 12) = x² - 4x + 3x - 12
= x(x - 4) + 3(x - 4)
= (x + 3)(x - 4)
Therefore. [tex]\frac{2}{x^{2}-x-12 }=\frac{2}{(x+3)(x-4)}[/tex]
2). [tex]\frac{1}{x^{2}-16 }[/tex]
Factored form of the denominator (x² - 16) = (x - 4)(x + 4)
[Since (a²- b²) = (a - b)(a + b)]
Therefore, [tex]\frac{1}{x^{2}-16 }=\frac{1}{(x-4)(x+4)}[/tex]
