Answer:
1st triangle:
sin(C): 0.64, [tex]\frac{16}{25}[/tex]
cos(C): 0.8, [tex]\frac{4}{5}[/tex]
Second triangle:
sin(C): 0.75, [tex]\frac{\sqrt{5} }{3}[/tex]
cos(C): 0.67, [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Using SOH CAH TOA, we know that to find the sin of an angle, it's Opposite/Hypotenuse.
To find the cos of an angle, it's adjacent/hypotenuse.
In the 1st triangle:
The adjacent to C is 16, the hypotenuse is 25.
[tex]\frac{16}{25} = 0.64[/tex] is the sin of C.
The adjacent to C is 20, and the hypotenuse is 25.
[tex]\frac{20}{25} = 0.8[/tex] is the cos of C.
In the second triangle:
The opposite to C is [tex]\sqrt{5}[/tex] and the hypotenuse is 2.
[tex]\frac{\sqrt{5} }{2} \approx0.75[/tex] is the sin of C.
The adjacent to C is 2 and the hypotenuse is 3.
[tex]\frac{2}{3} \approx 0.67[/tex] is the cos of C.
Hope this helped!
