Answer:
Step-by-step explanation:
1.
[tex]3 :7 \\Acute \: angle = 90\°\\7+3 = 10\\\frac{7}{10} \times 90\\\\= \frac{630}{10}\\ = 63 \°\\[/tex]
2.
[tex]Let \:the\: other\:acute \:angle\: be \:x\\According\:to \:the \:question ; \\ \:\\(2x-30)+x =90\\2x - 30 +x =90\\2x +x = 90+30\\3x = 120\\\frac{3x}{3} =\frac{120}{3} \\x = 40 \\\\(2x -30)\\2(40) -30\\80 - 30 = 50\\\\\\Angle \:1 = 50\°\\Angle \: 2 = 40\°\\[/tex]
